a letter and a number

时间限制：

3000 ms  |  内存限制：

65535 KB

难度：

1

 

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;

Give you a letter x and a number y , you should output the result of y+f(x).

 

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6R 1P 2G 3r 1p 2g 3

样例输出

191810-17-14-4

代码如下：

#include<stdio.h>

#include<string.h>

int main()

{

 int n,m;  

 char c;

 scanf("%d",&n); 

 while(n--)

 { 

  getchar();

  scanf("%c",&c);

  scanf("%d",&m);

  if(c>='a'&&c<='z')

   printf("%d\n",96-c+m);

  if(c>='A'&&c<='Z')

   printf("%d\n",c-64+m);

 }

 return 0;

}